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2 years ago

I need help plssssssssssssssssssssss

Mathematics

2 answers:

arlik [135]2 years ago

6 0

Answer:

it is blurry

Step-by-step explanation:

NeX [460]2 years ago

4 0

Answer:

Step-by-step explanation:

Given:

325 pages

90,000 words

Recommended reading: 200 words/ 1 minute

How many words on each page ?

90,000 words /325 pages ≈ 277 words / 1 page

Now see the picture.

The numbers for the difference I round them to the nearest word.

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Deshaun took 2 5/8 hours to clean the bathroom. Then took 1/4 hours to clean the den . How much total time did deshaun take to c

natulia [17]

Answer:

2.875 hours 2 5/8 plus 1/4 equals 2.875

7 0

3 years ago

What is 2m + 3m² - 4m ? Please show you work. :-)

Alchen [17]

Combine like terms
2m and -4m are like terms while 3m^2 isnt. So, leave 3m^2 as it is and combine the other set. 2m-4m = (-2m). Therefore, your answer should be 3m^2 - 2m

6 0

2 years ago

HELP ME ASAP PLEASEEEEEEE

Vlad [161]

Answer: a) about 450

Step-by-step explanation:

50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450

3 0

2 years ago

If you help will make you brainlest

Bumek [7]

Answer:

see below

Step by step explanation

$\because \: revenue = price \times demand \\ \therefore \: r(x) = x.d(x) \\ \therefore \: r(x) =x(200 - 2x) \\\therefore \: r(x) = \boxed{200x - 2 {x}^{2} }$

5 0

1 year ago

An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an

igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

$P(e_1)=0.90*0.67=0.603$

2) Left knee unsuccessful and right knee successful (X=1).

$P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067$

3) Right knee unsuccessful and left knee successful (X=1).

$P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297$

4) Both surgeries are unsuccessful (X=0).

$P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033$

Then, the mean can be calculated as the expected value:

$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

$V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111$

3 0

3 years ago