When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>
Equation :
MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)
K
= [M⁺] [OH⁻]
K = 1.39×10⁻¹² and [M⁺] = 0.001M
∴ 1.39×10⁻¹² = (0.001M) [OH⁻]
[OH⁻] = 1.004×10⁻¹⁹M
pOH = -log [OH⁻] = 11.9
pH = 14 - pOH
= 14 - 11.9
<u>pH = 2.1</u>
To learn more about solubility equilibrium ;
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Answer:
Option C = 200 mL
Explanation:
The volume of liquid remain same because students just transfer the liquid from the graduated cylinder with the capacity 250 mL to the graduated cylinder having the capacity of 500 mL. The volume of the liquid will remain same either it is in the large graduated cylinder or in a small graduated cylinder.
In order to determine if the ion is positively charged or negatively charged
