Answer:
What would be the value of g on the surface of the earth if its mass was twice and its radius half of what it is now ? g2=8g1 Thus , the value of g on the surface of the earth would be eight times the present value.
Explanation:
Hope this helps! :)
The production of a gas is different because unlike the heating curve, there was no heat applied to this experiment, and the experiment was a chemical reaction.
<h3>What is a Heating curve?</h3>
This shows the relationship between the temperature of the heating system and the air temperature in the outer environment.
The chemical reaction emitted heat as against the other which involved heat application which is why water formation in this curve was different.
Read more about Heating curve here brainly.com/question/14094062
#SPJ1
Answer:
Mass = 2.355 g
Explanation:
Given data:
Mass of K₂O needed = ?
Mass of KNO₃ produced = 5.00 g
Solution:
Chemical equation:
K₂O + Ca(NO₃)₂ → CaO + 2KNO₃
Number of moles of KNO₃:
Number of moles = mass/molar mass
Number of moles = 5.00 g/ 101.1 g/mol
Number of moles = 0.05 mol
now we will compare the moles of KNO₃ and K₂O.
KNO₃ : K₂O
2 : 1
0.05 : 1/2×0.05 = 0.025 mol
Mass of potassium oxide needed in gram:
Mass = number of moles × molar mass
Mass = 0.025 mol × 94.2 g/mol
Mass = 2.355 g
Co= 59g
S=32g
59+32=91g/mol
