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1 answer:
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Answer:
Step-by-step explanation:
We will use the standard formula for half-life:
Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:
We have a 3 gram sample. Therefore, our initial amount A₀ is 3:
And we want to find the remaining sample after 10 days. So, t=10. Substitute:
Use a calculator. So:
Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
Answer:
47, 40, 33, 26 are the first four terms of the sequence.
Step-by-step explanation:
Expression representing the sequence is,
where n = number of term in the sequence
For n = 1,
= 47
For n = 2,
= 47 - 7
= 40
For n = 3,
= 47 - 7(3 -1)
= 47 - 14
= 33
For n = 4,
= 47 - 21
= 26
Therefore, first four terms of the sequence are 47, 40, 33 and 26.