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Dimas [21]
3 years ago
11

On a map scale two neighboring towns are 2.4 inches apart. The actual straight line distance between the two towns is 36 miles.

What is the scale of the map?
Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

The scale of the map is 1 inch is <u>15 miles.</u>

Step-by-step explanation:

Given:

Distance of neighboring towns on map = 2.4 inches

Actual Distance of neighboring towns = 36 miles.

We need to find the scale of map;

Solution:

Now we know that;

On map 2.4 inches = 36 miles actual distance.

So on map 1 inch = Actual distance in 1 inch of scaling on map.

By using Unitary method we get;

Actual distance in 1 inch of scaling on map = \frac{36}{2.4} =15\ miles

Hence The scale of the map is 1 inch is <u>15 miles.</u>

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Please help me<br><br> Determine the value of base b if (152)b = 0x6A. Please show all steps.
egoroff_w [7]

Answer:

The value of b is, 8

Step-by-step explanation:

To determine the value of b:

Given:

(152)_b = 0x6A               ....[1]

Since, 0x6A represents the hexadecimal form.

To convert this hexadecimal form into decimal form:

(6A)_{16}= (6 \times 16^1)+(A \times 16^0)=(6 \times 16)+(10 \times 1) =96+10 = 106

⇒0x6A=106(decimal form)

Now we have to convert this decimal form into octal

8  |  106

8   |  13   | 2

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        1

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