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d1i1m1o1n [39]
3 years ago
9

Find the area of the composite figure

Mathematics
2 answers:
omeli [17]3 years ago
8 0

Answer:

the whole thing is 174

Step-by-step explanation:

Sunny_sXe [5.5K]3 years ago
3 0
Well cutting off the small 4x2 you get 8 plus’s the 7x2 is 14 so just add those together you should get 22in ^2
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This is literally my final send help pls
worty [1.4K]

Answer:

6.25

Step-by-step explanation:

5 is almost the half of it and 4 is the other/ sorry I'm not very good at explaining

8 0
2 years ago
Find an equation for the perpendicular bisect or of the line segment whose end points are (-2,-4) and (8,2)
Serhud [2]

Answer:

, you must find the midpoint of the segment, the formula for which is

(

x

1

+

x

2

2

,

y

1

+

y

2

2

)

. This gives

(

−

5

,

3

)

as the midpoint. This is the point at which the segment will be bisected.

Next, since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula

y

2

−

y

1

x

2

−

x

1

, which gives us a slope of

5

.

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of

5

is

−

1

5

.

We now know that the perpendicular travels through the point

(

−

5

,

3

)

and has a slope of

−

1

5

.

Solve for the unknown

b

in

y

=

m

x

+

b

.

3

=

−

1

5

(

−

5

)

+

b

⇒

3

=

1

+

b

⇒

2

=

b

Therefore, the equation of the perpendicular bisector is

y

=

−

1

5

x

+

2

.

4 0
3 years ago
What are two types of scientific investigations
vazorg [7]
Hypothesis and Analyses 
6 0
3 years ago
each pack of sugar free gum at a store cost $0.89 including tax if Evan pays $10.00 and receives $0.21 in change how many packs
babunello [35]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
A line passes through the points (-7, 2) and (1, 6).A second line passes through the points (-3, -5) and (2, 5).Will these two l
BlackZzzverrR [31]

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

Explanation:

Step 1. The first line passes through the points:

(-7,2) and (1,6)

and the second line passes through the points:

(-3,-5) and (2,5)

Required: State if the lines intersect, and if so, find the solution.

Step 2. We need to find the slope of the lines.

Let m1 be the slope of the first line and m2 be the slope of the second line.

The formula to find a slope when given two points (x1,y1) and (x2,y2) is:

m=\frac{y_2-y_1}{x_2-x_1}

Using our two points for each line, their slopes are:

\begin{gathered} m_1=\frac{6-2}{1-(-7)} \\  \\ m_2=\frac{5-(-5)}{2-(-3)} \end{gathered}

The results are:

\begin{gathered} m_1=\frac{6-2}{1-(-7)}=\frac{4}{1+7}=\frac{4}{8}=\frac{1}{2} \\  \\  \end{gathered}m_2=\frac{5+5}{2+3}=\frac{10}{5}=2

The slopes are not equal, this means that the lines are NOT parallel, and they will intersect at some point.

Step 3. To find the intersection point (the solution), we need to find the equation for the two lines.

Using the slope-point equation:

y=m(x-x_1)+y_1

Where m is the slope, and (x1,y1) is a point on the line.

For the first line m=1/2, and (x1,y1) is (-7,2). The equation is:

y=\frac{1}{2}(x-(-7))+2

Solving the operations:

\begin{gathered} y=\frac{1}{2}(x+7)+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+7/2+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+5.5 \end{gathered}

Step 4. We do the same for the second line. The slope is 2. and the point (x1,y1) is (-3, -5). The equation is:

\begin{gathered} y=2(x-(-3))-5 \\ \downarrow\downarrow \\ y=2x+6-5 \\ \downarrow\downarrow \\ y=2x+1 \end{gathered}

Step 5. The two equations are:

\begin{gathered} y=\frac{1}{2}x+5.5 \\ y=2x+1 \end{gathered}

Now we need to solve for x and y.

Step 6. Equal the two equations to each other:

\frac{1}{2}x+5.5=2x+1

And solve for x:

\begin{gathered} \frac{1}{2}x+5.5=2x+1 \\ \downarrow\downarrow \\ 5.5-1=2x-\frac{1}{2}x \\ \downarrow\downarrow \\ 4.5=1.5x \\ \downarrow\downarrow \\ \frac{4.5}{1.5}=x \\ \downarrow\downarrow \\ \boxed{3=x} \end{gathered}

Step 7. Use the second equation:

y=2x+1

and substitute the value of x to find the value of y:

\begin{gathered} y=2(3)+1 \\ \downarrow\downarrow \\ y=6+1 \\ \downarrow\downarrow \\ \boxed{y=7} \end{gathered}

The solution is x=3 and y=7, in the form (x,y) the solution is (3,7).

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

6 0
1 year ago
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