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klio [65]
3 years ago
13

In football, the path that a defender must run to tackle the ball carrier is called the path of pursuit. If the ball carrier run

s 40 yards to the end zone and the path of pursuit is 45 yards, how far apart were the ball carrier and defender when they started? Answer with appropriate precision. (Hint: Use the Pythagorean Theorem.)
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

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Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o
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Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is  x = 274 \ unites

Step-by-step explanation:

From the question we are told that

       The length of the vertical length is  x

      The length of the base leg is L = 330 + d units

      The length of the bisecting line segment is h

       The base angle is \theta  = 28^o

       The angle between d and line segment is  \theta_1 =  56^o

For the first angle

         Tan \theta_1 =  \frac{x}{d}

=>     d =  \frac{x}{Tan \theta _1}

 For the whole big triangle

      Tan \theta = \frac{x}{330 + d}

=>     d = \frac{x}{Tan \theta }  -330

So equating the both d

        \frac{x}{Tan \theta _1} =    \frac{x}{Tan \theta }  -330

Substitute values

        \frac{x}{Tan (56)} =    \frac{x}{Tan (28) }  -330

      0.6745 x =    1.880x  -330

       1.20549 x = 330

       x = 274 \ unites

     

   

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Step-by-step explanation:

espero te sirva

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