Answer:
<h3>1. 3.98 , 6.134 , 8.015</h3><h3>2. 0.541 , 0.521 , 0.314</h3><h3>3. 19.006 , 19.06 , 19.6</h3><h3>4. 0.7134 , 7.134 , 714.4</h3><h3>5. 590.817 , 5,190.18 , 509.107</h3>
Step-by-step explanation:
I HOPE IT HELPS :)
<span>8(3x + 6) + 13---expand using distributive property
=24x + 48+13 ...combine like terms
=24x +61....simplify
answer is C.24x + 61
hope it helps</span>
For this case we have the following equation:
H (t) = - 16t ^ 2 + 28t
When the dolphin finishes a jump, then the height is equal to zero.
We have then:
-16t ^ 2 + 28t = 0
We look for the roots of the polynomial:
t1 = 0
t2 = 1.75 s
Therefore, the dolphin takes 1.75 seconds to make a jump.
Answer:
it will take for the dolphin to make one jump about:
t = 1.75 s
Answer:(0,6)
Step-by-step explanation:
go to the left 3 points from T
then you go up 2 points from the number 4 which you should end up on after going over 3 spots.
Answer:
The tree is 16.25 m tall.
Step-by-step explanation:
Attached is a diagram that better explains the problem.
From the diagram we see that the distance between the top of the tree and the line of sight of the observer is x.
To find the height of the tree, we need to first find x and then add it to the height of the observers line of sight from the ground.
Using SOHCAHTOA trigonometric function:
tan(20) = x/39.2
=> x = 39.2 * tan(20)
x = 39.2 * 0.364
x = 14.27m
Hence, the height of the tree is:
(14.27 + 1.98)m
16.25m
The tree is 16.25 m tall.
