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sleet_krkn [62]
3 years ago
12

What is the LCD of 3/5, 1/10, 1/2

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
The LCD of 3/5 1/10and 1/2 is 10. This is because 10 is the smallest number that 5, 10 and 2 are all divisible by.
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Consider the following two loans for P=$12,000.
n200080 [17]

Answer:

Simple interest-?

Step-by-step explanation:

P= 12000

T=5yrs

R=5%

Now,

Simple interest - PTR/100

= 12000*5*5/100

= $3000

Again,

P=12000

T=3yrs

R=8%

Now,

Simple interest - PTR/100

= 12000*3*8/100

= $2880

Hope this helps.

4 0
2 years ago
There are 40 pupils in a class. 75% of them are present. How may are present? How many are absent?
Aleonysh [2.5K]

Answer:

30 are present 10 are absent

Step-by-step explanation:

75%=3/4

so 3/4 of them are absent

3/4(40)=30

and 40-30=10 are absent

8 0
2 years ago
Solve for x- <br> 6x^2 + 36x + 54 = 0
lions [1.4K]

Answer:

-3

Step-by-step explanation:

6x^2+36x+54=0

First, you can factor out a 6:

6(x^2+6x+9)=0

Next, you can factor the quadratic:

6(x+3)^2=0

Since the only value of x that could set this equation equal to 0 is -3, that is the answer. Hope this helps!

5 0
3 years ago
Find the y intercept​
erica [24]

Step-by-step explanation:

Slope of line ST = Slope of line PQ = -3.

y = -3x + c

When x = 3, y = -1

=> (-1) = -3(3) + c, c = 8

Therefore the equation of line ST is y = -3x + 8 and the y-intercept is 8.

7 0
3 years ago
Read 2 more answers
Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
3 years ago
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