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viktelen [127]
2 years ago
6

There are 15 members of the show choir. In how many different ways can you arrange any 8 members in the front row? Show work. I

will give brainliest!
Mathematics
1 answer:
Burka [1]2 years ago
3 0

Answer:

259,459,200 ways.

Step-by-step explanation:

That is the number of permutations of 8 from 15.

= 15! / 15-8!

= 15! / 7!

= 15*14*13*12*11*10*9*8

= 259459200

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Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra s
algol [13]

<em>f(x, y)</em> = <em>x</em> ² - 4<em>xy</em> + 5

has critical points where both partial derivatives vanish:

∂<em>f</em>/∂<em>x</em> = 2<em>x</em> - 4<em>y</em> = 0   ==>   <em>x</em> = 2<em>y</em>

∂<em>f</em>/∂<em>y</em> = -4<em>x</em> = 0   ==>   <em>x</em> = 0   ==>   <em>y</em> = 0

The origin does not lie in the region <em>R</em>, so we can ignore this point.

Now check the boundaries:

• <em>x</em> = 1   ==>   <em>f</em> (1, <em>y</em>) = 6 - 4<em>y</em>

Then

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 6 when <em>y</em> = 0

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -2 when <em>y</em> = 2

• <em>x</em> = 4   ==>   <em>f</em> (4, <em>y</em>) = 12 - 16<em>y</em>

Then

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 12 when <em>y</em> = 0

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -4 when <em>y</em> = 2

• <em>y</em> = 0   ==>   <em>f</em> (<em>x</em>, 0) = <em>x</em> ² + 5

Then

max{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 21 when <em>x</em> = 4

min{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 6 when <em>x</em> = 1

• <em>y</em> = 2   ==>   <em>f</em> (<em>x</em>, 2) = <em>x</em> ² - 8<em>x</em> + 5 = (<em>x</em> - 4)² - 11

Then

max{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -2 when <em>x</em> = 1

min{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -11 when <em>x</em> = 4

So to summarize, we found

max{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = 21 at (<em>x</em>, <em>y</em>) = (4, 0)

min{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = -11 at (<em>x</em>, <em>y</em>) = (4, 2)

5 0
3 years ago
A player on the school baseball team reaches first base 710 of the times he is at bat. Out of 70 times at bat, how many times wo
Murrr4er [49]

Answer:

I predict that he will reach first base

out of 70 times at bat. answer: 3

Step-by-step explanation:

4 0
3 years ago
Jack wants to fill a rectangular box with sand. The length of the sand box is 3 feet, width is 6 inches, and height is 2.4 inche
Aleksandr-060686 [28]
Jack would need to buy 2 bags of sand.
To find the answer you first have to find the volume of the rectangular box which can be found using the formula length times width times height (remember that the numbers have to have the same unit so it would look like 3 times .5 times .2 if you convert them all the feet). the volume of the box is equal to .3
Then you could set the volume of the box equal to .15x to find how many boxes he would need. The formula would be .15x=.3
Divide by .15 to get x alone and you get 2 for the answer.
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3 years ago
Read 2 more answers
Add (y + 2x + 5) + (3y - 3x +1)
Nezavi [6.7K]

Answer:

4y-x+6

Step-by-step explanation:

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Manuel hizo un viaje en el coche, en el cual consumió 20 litros de gasolina. El trayecto lo hizo en dos partes: en la primera, c
Alona [7]

Responder:

24 litros; 16 litros; 4 litros

Explicación paso a paso:

Dado que:

Gasolina consumida = 20 litros

Sea la cantidad de gasolina en el tanque = x

Primera parte del viaje = 2/3 de x

Segunda parte del viaje = 1/2 de (x - 2x / 3)

Cantidad de gasolina en el tanque:

2x / 3 + 1/2 (x - 2x / 3) = 20

Solución para x

2x / 3 + x / 2 - x / 3 = 20

(4x + 3x - 2x) / 6 = 20

5 veces / 6 = 20

5 veces = 20 * 6

5 veces = 120

x = 120/5

x = 24

Cantidad de gasolina en el tanque = 24 litros

Litros consumidos en cada etapa:

Primera parte = 2/3 de 24 = 48/3 = 16 litros

2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros

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3 years ago
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