Answer:
Equation for the problem
3x + 15 = 51 laps
Hence
She swims on
Monday: 12 laps
Wednesday : 12 laps
Friday = 12 laps
Step-by-step explanation:
Ella swims four times a week at her club's pool.
We are told that:
She swims the same number of laps on Monday, Wednesday, and Friday.
Hence, the number rod times that she swims on Monday, Wednesday and Friday is represented by x
Also, she swims 15 laps on Saturday. She swims a total of 51 laps each week. Equation for the problem
= x + x + x + 15 = 51 laps
3x + 15 = 51 laps
Hence
3x = 51 - 15
3x = 36
x = 36/3
x = 12 laps
Therefore, She swims on:
Monday: 12 laps
Wednesday : 12 laps
Friday = 12 laps
The answer to your question is Y= 3 because 18/3 = 6 and 9/3 = 3 so Y=3
In this case, we can use the z statistic to find for the proportion
of students who failed the exam. The formula for z score is given as:
t = (x – u) / s
where,
x = the sample score = 60
u = sample score mean = 82
s = standard deviation = 11
Substituting all given values into the equation:
t = (60 – 82) / 11
t = - 2
Based from the standard proportion distribution tables for
z, this corresponds to:
P = 0.0228
This means that 2.28% of the students failed the exam or
equivalent to:
failed students = (0.0228) * 85 = 1.938
<span>approximately 2 students failed the exam</span>
Hey there!
Let's set up our expression:
(7a-6b+7)-(8a-2)
In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:
7a-6b+7-8a+2
Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:
(7a-8a) - 6b + (7+2) =
-a - 6b + 9
Hope this helps!
You start off with 4*(cos(x+(pi/3)))
Let's place the 4 aside for the time being:
Cos(u+j) = cos(u)*cos(j) - sin(u)*sin(j)
cos(x+(pi/3)) = cos(x)*cos(pi/3) - sin(x)*sin(pi/3)
cos(x+(pi/3)) = cos(x)/2 - (sqrt(3)/2)*sin(x)
Multiplying by the 4 we put aside:
4*cos(x+(pi/3)) = 2*cos(x) - 2*sqrt(3)*sin(x)
The correct answer is B
