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3 years ago

If 3 + √5/ 2√5 + 3 = a + b√5, find the values of rational numbers a and b.

Mathematics

1 answer:

Feliz [49]3 years ago

6 0

Answer: The given question is solved :

Step-by-step explanation:

correct solution in imaje

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The fare for a taxi cab is $2.50 per passenger and $0.75 for each mile. A group of friends has $22.00

xeze [42]

For this case we have to:

x: Let the variable representing the number of people to travel in the group

y: Let the variable representing the number of miles traveled.

If friends only have $22 then we have the following inequality:

$2.50x + 0.75y \leq22$

Now, if there are three people in the group we have that $x = 3.$

$2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33$

The taxi can travel a maximum of 19.33 miles.

On the other hand, if the group wants to travel 10 miles then we have to y = 10.

$2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8$

Thus, they could travel a maximum of 5 people.

ANswer:

$2.50x + 0.75y \leq22$

Traveling 3 people, the taxi can travel a maximum of 19.33 miles

Traveling 10 miles, a maximum of 5 people can travel

7 0

3 years ago

I need help ASAP there’s a time limit

andreyandreev [35.5K]

14 uehebeudygwgwvbsbbe

3 0

3 years ago

I know it is basic but I need help 11m+13=m+23

zloy xaker [14]

Answer:

m = 1

Step-by-step explanation:

11m + 13 = m + 23

Get m by itself by subtracting m from both sides.

10m + 13 = 23

Subtract 13 from both sides.

10m = 10

DIvide by 10.

m = 1

8 0

3 years ago

Read 2 more answers

Need help with this

AleksandrR [38]

Step-by-step explanation:

$\cos( \beta ) + \sin( \beta ) \tan( \beta ) = \sec( \beta )$

$\cos( \beta ) + \sin( \beta ) \frac{ \sin( \beta ) }{ \cos( \beta ) }$

$\cos( \beta ) + \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }$

$\frac{ \cos {}^{2} ( \beta ) }{cos \beta } + \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }$

$\frac{1}{ \cos( \beta ) }$

$= \sec( \beta )$

3 0

3 years ago

Read 2 more answers

Simplify: 18q2−45q+25/9q2−25.

Svet_ta [14]

Answer:

$\frac{(6q-5)}{(3q+5)}$

Step-by-step explanation:

Given: $\frac{18q^{2}-45q+25 }{9q^{2}-25 }$

Factorizing the numerator and the denominator, we have:

18 $q^{2}$ - 45q + 25 = 18 $q^{2}$ - 30q - 15q + 25

= (3q - 5)(6q - 5)

and

9 $q^{2}$ - 25 = (3q - 5)(3q + 5)

So that,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}$

= $\frac{(6q-5)}{(3q+5)}$

Therefore,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(6q-5)}{(3q+5)}$

5 0

3 years ago