Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = -
( 2 ) + c
Or, 6 = -
+ c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = -
x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
A
x=75°
B
We know that ∠EFG=∠ABF because they are corresponding angles.
We also know that ∠x+∠ABF=180, because angles along a straight line always equal 180:
x+105=180
x=75°
You can name a vector<span> by its length and direction</span>
Answer:
xº=71º
Step-by-step explanation:
Take the triangle BDH
Once the sum of interior angles of a triangle is 180º:
40º+31º+yº=180º
71º+yº=180º
yº=109º
Once yº and xº are supplementary angles (add up to 180º):
yº+xº=180º
109º+xº=180º
xº=71º
The system shown at the right has no solution, as the grahs never intersect.
On the other hand, the line and the parab. at the left do intersect, and the points of intersection are (-3,0) and (6,6).