I don’t know the answer but I need points sorry
Answer:
Y' = -xsin(2x) + 2cos(2x)
Step-by-step explanation:
For this problem, we will need to use the product rule since you have two terms that contain the variable x.
The product rule is simply as follows:
The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.
Note the derivative of 2x with respect to x, is 2.
Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).
With this in mind, let's find the derivative of our function with respect to x.
Y = 2xcos2x
Y = 2x * cos(2x)
Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)
Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)
Y' = (-x)sin(2x) + 2cos(2x)
So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.
Cheers.
3 because a polygon has 3 or more sides
a) x=4 is 5 units to the right of x=-1.
y=12 is 4 units up from y=8.
Your point (-1, 8) is translated to (4, 12).
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b) If the parent function f(x) = x is translated so it goes through (4, 12), the translated function can be written ...
... g(x) = f(x-4) +12 = (x -4) +12
... g(x) = x +8
