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aalyn [17]
2 years ago
9

There are 20 black, 15 white, 12 green, 12 red, 9 blue and 2 yellow candies in a box. How many candies should you take (without

looking at them) to be sure that you have at least 3 candies the same color?
Mathematics
1 answer:
kow [346]2 years ago
4 0
<h3>Answer:  13</h3>

=============================================================

Explanation:

The best case scenario is that you get 3 of the same color in a row on the first three attempts. The lower bound is 3.

However, we have to consider the worst case scenario when we want to guarantee something like this, without looking at the candies we selected.

Consider the case of something like this sequence:

  1. black
  2. white
  3. green
  4. red
  5. blue
  6. yellow
  7. black
  8. white
  9. green
  10. red
  11. blue
  12. yellow
  13. black

As you can see above, I've listed the colors in the order presented by your teacher. I pick one candy at a time. Once I reach yellow, I restart the cycle. In slots 1, 7 and 13, we have a black candy selected. This example shows that we must make 13 selections to guarantee that we get at least 3 candies of the same color (that color being black). The order of the candies selected doesn't matter. We could easily use any other color except yellow to do this example. The black candy just happened to be the first listed, so I went with that.

Note how we have 6 unique colors in the set {black, white, green, red, blue, yellow}. If we pick 2 candies of each color, then we've selected 6*2 = 12 candies so far. That 13th candy (some color other than yellow) is guaranteed to be a color we already selected; therefore, we'll be guaranteed to have 3 of the same color. We won't know what color it is but we will know we have a match like this.

For more information, check out the Pigeonhole Principle.

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The basketball boosters are selling school t-shirts for 20 dollars and pants for 45 dollars. Last week they sold 100 items and c
lana66690 [7]

He sold 76 shirts and 24 pants.

Step-by-step explanation:

Given,

Cost of one t-shirt = $20

Cost of one pants = $45

Total items sold = 100

Total sales = 2600

Let,

x be the number of t-shirts

y be the number of pants

According to given statement;

x+y=100    Eqn 1

20x+45y=2600   Eqn 2

Multiplying Eqn 1 by 20

20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600

Dividing both sides by 25

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Putting in Eqn 1

x+24=100\\x=100-24\\x=76

He sold 76 shirts and 24 pants.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/289820
  • brainly.com/question/2826639

#LearnwithBrainly

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3 years ago
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