3 years ago

Find the derivative of the function

1 answer:

4 0

$f(x)=-2x^3+5\sin(x)\\\\f'(x)=(-2x^3+5\sin(x))'=(-2x^3)'+(5\sin(x))'\\\\=3\cdot(-2x^2)+5\cdot\cos(x)=-6x^2+5\cos(x)\to D.$

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salantis [7]

Answer:

$\frac{10}{11}$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

In the right triangle ABC

$sin(g^o)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(g^o)=\frac{x}{z}$

$sin(g^o)=\frac{10}{11}$

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blsea [12.9K]

Step-by-step explanation:

An + c = d

an=d-c

a=(d-c)/n is your answer

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emmasim [6.3K]

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Paha777 [63]

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