Answer:

Step-by-step explanation:
The rate of change (slope) is 1 which is more than function 2 and less than function 1

Normal-travel DATA:
distance = 240 km
rate = x km/h
time = d/r
= 240/x hrs
_______________________
Bad weather DATA:
distance = 240 km
rate = (x-20) km/h
time = 240/(x-20) hrs
______________________
Bad time - normal time = 2 hrs
240/(x-20) - 240/x = 2
120/(x-20) - 120/x = 1
120x -120(x-20) = x(x-20)
20 = x^2 -20x
x^2 - 20x - 20 = 0
x = [20 +- sqrt(20^2 - 4*1*-20)]/2
x = [20 +- sqrt(480)]/2
x = [20 +- 4sqrt(30)]/2
x = 10 +- 2sqrt(30)
Degree is 4 and coefficient is 1
For this problem, you haven = 360p = 1/6q = 5/6 E[x] = np = 360*1/6 = 60SD[x] = √(npq) = √(360*1/6*5/6) = √(50) ≈ 7.07