Answer:
Explained below.
Step-by-step explanation:
Denote the variable as follows:
M = male student
F = female student
Y = ate breakfast
N = did not ate breakfast
(a)
Compute the probability that a randomly selected student ate breakfast as follows:
(b)
Compute the probability that a randomly selected student is female and ate breakfast as follows:
(c)
Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:
(d)
Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:
(e)
Compute probability of the student selected "is male" or "did not eat breakfast" as follows:
(f)
Compute the probability of "is male and did not eat breakfast as follows:
Answer:
30
Step-by-step explanation:
1.Substitute the x for 12.
2.Multiply the 2 by 12.
3.Then add 6 to your answer.
This is the transformations: See the picture, here we find the coordinate:
A' = (2,-3) and A''=(0.5,-2). There is many ways to get back to A from A'', i have showed one way (the red lines). This is done by going 5 units right and then 6 units up.
see image at https://imgur.com/a/fWQl8
The answer would be -1/6 or -0.166667
Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
