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Brums [2.3K]
3 years ago
9

Question 8

Chemistry
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

<em>The water also feels cool because water has a bigger specific heat than sand. Despite the water receiving the same amount of energy for the same amount of time as the sand, the water needs more energy to change one gram of the water one degree Celsius.</em>

Explanation:

<em>At a sunny day at the beach, the top of the sand is warm. The radiation from the Sun heats up the surface of the sand, but sand has a low thermal conductivity, so this energy stays at the surface of the sand. When you dig your feet into the sand it is cool below because the energy from the Sun was not transferred below the surface of the sand. </em>

<em> Water has a higher thermal conductivity, meaning the energy from the Sun is quickly transferred throughout the water, a big area. This means the heat will be even throughout the water, taking a lot more energy than is supplied to finally heat up the entire ocean. The water also feels cool because water has a bigger specific heat than sand. Despite the water receiving the same amount of energy for the same amount of time as the sand, the water needs more energy to change one gram of the water one degree Celsius. It takes 1 calorie of energy from the Sun to change one gram of the water one degree Celsius, while sand only needs 0.2 calories of energy from the Sun to change the same amount. This means it will take longer for the water to increase in temperature because water needs more energy to do so. </em>

<em> Another factor contributing to water temperature is the angle of the Sun. If the Sun is shining on the water from an angle, some of the light is reflected. When the light is reflected the energy is not being absorbed, so the temperature is not increasing as much. When the Sun is high in the sky above the water, the energy will be absorbed because the light is not being reflected.</em>

Elina [12.6K]3 years ago
4 0
WELL SUMMMER. TIME ITS hot but winter time its cold
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Answer:

1.135 M.

Explanation:

  • For the reaction: <em>2HI → H₂ + I₂,</em>

The reaction is a second order reaction of HI,so the rate law of the reaction is: Rate = k[HI]².

  • To solve this problem, we can use the integral law of second-order reactions:

<em>1/[A] = kt + 1/[A₀],</em>

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t is the time of the reaction (t = 8 hours x 60 x 60 = 28800 s),

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[A] is the remaining concentration of HI after hours ([A₀] = 0.75 M).

∵ 1/[A] = kt + 1/[A₀],

∴ 1/[A₀] = 1/[A] - kt

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<em>So, the concentration of HI 8 hours earlier = 1.135 M.</em>

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