Answer:
solubility of X in water at 17.0 
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0 can be calculated using the information given.
Let's assume solubility of X in water at 17.0 is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y = 
= 0.11
Hence solubility of X in water at 17.0 is 0.11 g/mL.
There are 2.5 oxygen for every phosphorus atom.
Sickness? Srry for not knowing
I believe c. I hope it helps :)
Answer:
The retention factor, k is 2.49
Explanation:
According to the theory of High-Performance Liquid Chromatography (HPLC), the retention factor (or capacity), k, of a column is the ratio of the retention time of a retained analyte (toluene) to that of the un-retained solute (methane).
This implies that:
k = 
= 
retention factor, k = 2.49.
Note that there is no unit for retention factor, as it is a ratio.
