Answer:
The limiting reactant is oxygen gas and the reaction would produce 3.932 x 10 ^ 7 moles of water
Explanation:
Step 1: Convert everything into moles
nH2(l) = 1.06 x 10^8 g / 2.016 g/mol = 5.26 x 10^7 mols
nO2(l) = 6.29 x 10^8 g / 32.00 g/ mol = 1.966 x 10^7 mols
Step 2: Find the limiting reagent
The limiting reagent would be oxygen gas from
the balanced equation because we have less moles of oxygen gas needed to fully combust with the hydrant gas
Step 3: Stoichiometry time
The mole ratio from oxygen gas to water is 1:2
This means that for every mole of oxygen gas two moles of water is produced
We need to multiply the moles of oxygen gas by two to find out how many moles of water has been produced
nH2O = nO2 x 2
nH2O = 1.966x10^7 x 2
nH2O = 3.932x10^7
Step 4: Therefore statement
Therefore the limiting reactant is oxygen gas and the reaction would produce 3.932 x 10 ^ 7 moles of water
Answer:
1.12 x 10²³atoms of F
Explanation:
Number of MgF₂ atoms = 5.6 x 10²² molecules;
The unknown here is the number of Fluorine atoms found in the compound.
In MgF₂,
1 mole of MgF₂ contains 2 moles of F;
From the given number of molecules we can also say that, MgF₂ contains 5.6 x 10²²atoms;
1 mole of MgF₂ contains 2 moles of F;
5.6 x 10²²atoms of MgF₂ will contain 2 x 5.6 x 10²² = 1.12 x 10²³atoms of F
Answer:
<h3>Burning, cooking, rusting and rotting are examples of chemical changes.</h3>
I just got this question and it was lipids sorry if i’m wrong
