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GuDViN [60]
2 years ago
11

Help me asap I'll mark brainliest!!!!!!!!!

Mathematics
1 answer:
pshichka [43]2 years ago
3 0

Answer:

NO!!!! NO!!!! NOOOOOO!!!!!!!

Step-by-step explanation:

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What are the next 3 numbers in the number sequence?
PSYCHO15rus [73]

Answer:

B

Step-by-step explanation:

31-23=8

41-31=10

53-41=12

So next number should be 53+14, that is 67.

Follow the rule:

67+16=83

83+18=101

3 0
3 years ago
Read 2 more answers
Urgent!!!!!!!!!!!!!!!!!!
MAVERICK [17]
24 right box VEDR - 6(4)
9 Left triangle VMR - 0.5 (6)(3)
24 + 9 = 33
6 0
2 years ago
A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude
DaniilM [7]

Answer:

The answer is "\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\"

Step-by-step explanation:

Given values:

\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39

Using formula:

\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\

Put the values in the above formula:

\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\

4 0
3 years ago
In Janie's homeroom 54% of the students' families own a dog and 32% own a dog and a cat. What is the probability that a student'
pogonyaev

Answer:

51,111%

Step-by-step explanation:

We know that 45% have a dog but no cat.  While 23% have both a dog and a cat.

Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)

= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%

The probability that a student’s family owns a cat if the family owns a dog is 51,111%

6 0
3 years ago
PLEASE HELP QUICK I CANT FAIL THIS TEST
Finger [1]

Answer:

24+24x I believe is the answer. Good luck on your test :)

5 0
4 years ago
Read 2 more answers
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