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2 years ago

Consider if each set of ordered pairs represents a function

Mathematics

1 answer:

Natasha2012 [34]2 years ago

8 0

Answer:

that'll be cool

Step-by-step explanation:

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Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16).

Luden [163]

The y-value is the one on the right. Therefore, the y-value of P is 6. Following the rule, the y-value of P' is 6-16= -10.

8 0

3 years ago

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Solve the quadratic equation by factoring. 9x^2+24x+20=4

const2013 [10]

D. -4/3

Let's solve your equation step-by-step.

9x2+24x+20=4

Step 1: Subtract 4 from both sides.

9x2+24x+20−4=4−4

9x2+24x+16=0

Step 2: Factor left side of equation.

(3x+4)(3x+4)=0

Step 3: Set factors equal to 0.

3x+4=0 or 3x+4=0

x= −4 /3

Hope This helps

5 0

2 years ago

Will do brainly for this

Tcecarenko [31]

Answer:

180 Degrees

Step-by-step explanation:

I had the same question and it worked/correct.

6 0

3 years ago

If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$

It must be negative due to its presence in Fourth quadrant.

Hence, $\sin \theta=\frac{-45}{53}$

7 0

3 years ago

What two numbers are missing from this factor tree for the prime factorization of 252?

ElenaW [278]

Answer:

c. 3 and 21

Step-by-step explanation:

6 0

6 months ago

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