Answer:
259/30 or 8 19/30 depending on what format your teacher wants the answer
Step-by-step explanation:
First we can turn both mixed fractions into improper fractions and to do that we multiply the whole number by the denominator and that add that to the top number. So for 3 4/5 we would multiply 3 and 5 and than add 4 getting us to 19/5 doing the same to 4 5/6 gets us to 29/6. Now in order to add fractions we need to get a common denominator. The least common multiple of 5 and 6 is 30 so we will multiply each fraction by whatever number will give us 30 in the denomiator. for 19/5 that number is 6 so our new fraction is 114/30 and for 29/6 that number is 5 so our new number is 145/30. Now we just add the numerators and simplify. 114/30+145/30=259/30
I hope this helps and please don't hesitate to ask if there is anything still unclear!
Answer:
1,260
Step-by-step explanation:
6x3=18 7000÷18=1,260
Answer:
Total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200
Step-by-step explanation:
We have given number of students = 10
These 10 students are assigned to four dorm rooms a single, a double, a triple and a quad
So number of ways to assigned single student ![=^{10}C_1=\frac{10!}{1!9!}=10\\](https://tex.z-dn.net/?f=%3D%5E%7B10%7DC_1%3D%5Cfrac%7B10%21%7D%7B1%219%21%7D%3D10%5C%5C)
Now left student = 10 -1 = 9
So number of ways to assigned double student ![=^{9}C_2=\frac{9!}{2!7!}=36](https://tex.z-dn.net/?f=%3D%5E%7B9%7DC_2%3D%5Cfrac%7B9%21%7D%7B2%217%21%7D%3D36)
Now left student = 9-2 = 7
So number of ways to assigned triple student
=70
Now left student = 7 - 3 = 4
So number of ways to assigned quad student ![=^{4}C_4=\frac{4!}{4!0!}=1](https://tex.z-dn.net/?f=%3D%5E%7B4%7DC_4%3D%5Cfrac%7B4%21%7D%7B4%210%21%7D%3D1)
So total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200
Answer:
-3
Step-by-step explanation:
9-3(2)2
9-(6)2
9-12
-3