The equation of the line is y = 0.8x - 1.4 if the slope of the line is 0.8 and line passes through coordinates (-2,-3)
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:

The slope m = 0.8
The line passing through coordinates (-2,-3)
y = mx + c
y = 0.8x + c
Plug the point in the equation.
-3 = 0.8(-2) + c
c = -1.4
y = 0.8x - 1.4
Thus, the equation of the line is y = 0.8x - 1.4 if the slope of the line is 0.8 and line passes through coordinates (-2,-3)
Learn more about the straight line here:
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first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
Answer:
The equation is y=4/3x+4
Step-by-step explanation:
Answer:
x = 15
Step-by-step explanation:
20^2 + x^2 = 25^2
400 + x^2 = 625
subtract each side 400
it results to 225
square root 225, to equals this -->
X = 15
The answer is "alternate exterior angles theorem."