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Arada [10]
2 years ago
11

Please help this question

Mathematics
1 answer:
3241004551 [841]2 years ago
4 0

Answer:

Theres no question here so....yeah

Step-by-step explanation:

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Circle J is congruent to circle P. Circles J and P are congruent. Chords O K and Q R are congruent and chords K M and R T are co
Molodets [167]

Answer: 9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
-27=x-15 please someone help me
nadezda [96]

Answer: x = −12

Step-by-step explanation:

−27 = x −15

x − 15 = −27

x − 15 + 15 = −27 + 15

x = −12

5 0
3 years ago
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In an isolated environment, a disease spreads at a rate proportional to the product of the infected and non-infected populations
eimsori [14]

Answer:

Expression: N = C·L·l(t)· T + 20

The initial value problem and solution are expressed as a first order differential equation.

Step-by-step explanation:

First, gather the information:

total population, N = 2 000

Proportionality constant, C = 0.0002

l(t) number of infected individuals = l(t)

healthy individuals = L

The equation is given as follows:

N = C·L·l(t)

However, there is a change with time, so the expression will be:

\frac{dN}{dt} = C·L·l(t)

multiplying both sides  by dt gives:

dN  =   C·L·l(t)

Integrating both sides gives:

\int\limits^a_b {dN} \, dt = \int\limits^a_b {CLl(t)} \, dt

N = C·L·l(t)· T + K

initial conditions:

T= 0, N₀ = (0.01 ₓ 2 000)  = 20

to find K, plug in the values:

N₀ = K

20 = K

At any time T, the expression will be:

<u>N = C·L·l(t)· T + 20</u> Ans

8 0
3 years ago
Divide 6 divided by 3/5 <br><br><br> Answer only if u know please:)
meriva

Answer:

The answer is 10 or 10/1

3 0
2 years ago
A basketball player shoots a basketball that reaches a height above 15 feet before landing back on the ground exactly after 7 se
Papessa [141]

Answer:

I and IV

Step-by-step explanation:

Since the height of the basketball reaches above 15 feet, hence the maximum of the function should be greater than 15 feet. Also at 7 seconds, the ball is on the ground, hence f(7) = 0 feet

The maximum of a function is at x = -b/2a

i) f(x) = -(x-3)² + 16 = -(x² - 6x + 9) + 16 = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 16 = 16 > 15

Also f(7) = - (7 - 3)² + 16 = 0

Hence this option is correct

ii) f(x) = -x² + 8x - 7

The maximum of a function is at x = -b/2a = -8 / 2(-1) = 4

f(4) = -4² + 8(4) - 7 = 9 < 15   not correct

Also f(7) = - 7² + 8(7) - 7 = 0

Hence this option is not correct since the maximum f(4) = 9 < 15  

iii)  f(x) = -(x-3)² + 14 = -(x² - 6x + 9) + 14 = -x² + 6x + 5

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 14 = 14 < 15

Also f(7) = - (7 - 3)² + 14 = -2

Hence this option is not correct since the maximum f(4) = 9 < 15 and f(7) ≠ 0

iv)f(x)  = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3)² + 6(3) + 7 = 16 > 15

Also f(7) = - (7)² + 6(7) + 7 = 0

Hence this option is correct

3 0
3 years ago
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