Answer:
Time period of the oscillation will be 0.695 sec
Explanation:
We have given mass attached to the string m = 0.350 kg
The spring is stretched by 0.120 m
So x = 0.120 m
We know that force is given by F = Kx
So mg = kx
k = 28.5833
Now time period is given by
So time period of the oscillation will be 0.695 sec
Answer:
2324 J
Explanation:
The formula for work is:
where is the force applied, and
is the distance moved, in this case
and we need to find
Since the crate is not moving up or down, we conclude that the <u>normal force must be equal to the weight </u>of the object:
where is the normal force and
is the weight, which is:
, where g is the gravitational acceleration
and
is the mass
.
---------
Thus the normal force is:
Now, the force due to the friction is defined as:
where is the coefficient of friction,
So, for the crate to move, the force applied must be equal to the frictional force:
And now that we know the force we can calculate the work:
substituting known values: