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Vilka [71]
3 years ago
15

What do you know about velocity, acceleration and reference frame?

Physics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down. ... Acceleration is defined as the change in the velocity vector in a time interval, divided by the time interval.

In physics and astronomy, a frame of reference consists of an abstract coordinate system whose origin, orientation, and scale are specified by a set of reference points ― geometric points whose position is identified both mathematically and physically.

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A cylinder of mass 14.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed o
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b) 283.5J

c)850.5J

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The expression for the translational kinetic energy is,

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14kg for m

9m/s for v

E_r = \frac{1}{2} (14) (9)^2\\= 567J

The translational kinetic energy of the center of mass is 567J

(B)

The expression for the rotational kinetic energy is,

E_R = \frac{1}{2} Iw^2

The expression for the moment of inertia of the cylinder is,

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The expression for angular velocity is,

w = \frac{v}{r}

substitute

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in equation for rotational kinetic energy as follows:

E_R = (\frac{1}{2}) (\frac{1}{2} mr^2)(\frac{v}{r} )^2

= \frac{mv^2}{4}

E_R = \frac{14 \times 9^2 }{4} \\\\= 283.5J

The rotational kinetic energy of the center of mass is 283.5J

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The expression for the total energy is,

E = E_r + E_R\\\\

substitute 567J for E(r) and 283.5J for E(R)

E = 567J + 283.5\\= 850.5J

The total energy of the cylinder is 850.5J

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