It is 52.243 because, well, you have 52 and then the fraction is the only thing less than zero.
Answer:
6 and 7
Step-by-step explanation:
To do this, we need to look at the two closest numbers that are divisible by 6. These are 36 and 42.
As 37 is between 36 and 42, the quotient must be between 6 and 7
Answer:
1.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
Since the warranty on a machine specifies that it will be replaced at failure or age 4 and the distribution for X is defined between 0 and 5 then if we define the random variable Y ="the age of the machine at the time of replacement" we know that the values for Y needs to be between 0 and 4 or between 4 and and we can define the following density function:
for other case
Now we can apply the definition of expected value and we have this:
And for the second moment we have:
And the variance would be given by:
Answer:
Slope = -1/4
y-intercept = 1
Step-by-step explanation: