9514 1404 393
Answer:
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
Question 2. :
8^2 = 64 and 9^2 = 81, therefore the square root of 65 falls between these two values, 8 and 9, 64<65<81
Question 3. :
13^2 = 169 and 14^2 = 196, the correct answer is square root of 175, because 169<175<196
Hope this helps, you only need to know the squared values and square roots.
Answer:
"f(x)
domain: all real numbers, range: all real numbers
f–1(x)
domain: all real numbers, range: all real numbers"
Step-by-step explanation:
We can use the fact that the domain of a function and the range of its inverse are equal.
Also, the range of the function and the domain of its inverse are equal as well.
<em>Looking at the function f(x/ = -x + 5, we see that this is a line with a negative slope of 1 and a y-intercept of +5. </em>
As we know from the graph of lines, there is no restricting values in x and y. So for the original function, domain is the set of all real numbers and the range is the set of all real numbers.
For the inverse, the range is set of all real numbers and domain is also the set of all real numbers.
First answer choice is right.
1:option(c)
2:option(c) again
