Question

Monte performs an experiment using 2 identical graduated cylinders, each with a radius of 2 centimeters. The volume of the liquid in the first graduated cylinder is 188.4 cubic centimeters. The volume of the liquid in the second graduated cylinder is 314 cubic centimeters.
What is the difference in the height of the liquid in the two cylinders?

Use 3.14 for pi.               PLZZ I NEED ANSER FAST

Answer 1

Πr²h(2)-πr²h(1)=πr²(h(2)-h(1))=V2-V1
V2-V1=πr²(h(2)-h(1))

314-188.4=π*2²(h(2)-h(1))
(h(2)-h(1))=(314-188.4)/4π=10
difference is 10 cm

Answer 2

Recall the formula for the volume of a cylinder: $V=\pi r^2h$

Let's plug in: $188.4=3.14\cdot2^2h_1$ so $h_1=15$.  $314=3.14\cdot2^2h_2$ so $h_2=25$

The difference between $h_1\text{ and }h_2$ is 25-15=10 cm.