Radius is half that of the diameter and area =pi times radius squared then the area wouldn't be decimal format if it was while number I have no idea without looking at my notes... Coffee here I come
<h2>Solving Equations with Absolute Expressions</h2><h3>
Answer:</h3>
<u>No Solutions</u>
<h3>
Step-by-step explanation:</h3>
Given:

Rewriting the given equation:

We have to realize that the right side of the equation,
, will always be positive no matter what real values of
(because we're taking the absolute value of the expression) and we are equating it to a <em>negative</em> constant number,
. Something that is always positive will never be negative so there's no value for
that satisfies the solution.

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Solving by positive of the expression:

Solving by the negative of the expression:

Checking: 

is an extraneous solution.
Checking: 

is an extraneous solution.
Answer:
![[x - 1][x + 1][{x}^{2} + 4]](https://tex.z-dn.net/?f=%5Bx%20-%201%5D%5Bx%20%2B%201%5D%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
Step-by-step explanation:
Knowing that you have to find two numbers that when they differ to 3, they also multiply to −4, and those numbers are −1 and 4. So, after clearing that up, you will have this [since our degree of this polynomial function is 4]:
![[{x}^{2} - 1][{x}^{2} + 4]](https://tex.z-dn.net/?f=%5B%7Bx%7D%5E%7B2%7D%20-%201%5D%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
Then, since
is factorable, you will get this:
![[x - 1][x + 1]](https://tex.z-dn.net/?f=%5Bx%20-%201%5D%5Bx%20%2B%201%5D)
Finally, attach
to the partially factored polynomial to get this:
![[x - 1][x + 1][{x}^{2} + 4]](https://tex.z-dn.net/?f=%5Bx%20-%201%5D%5Bx%20%2B%201%5D%5B%7Bx%7D%5E%7B2%7D%20%2B%204%5D)
I am joyous to assist you anytime.
The radius of a period on this page
This is because people usually write numbers that are very big/small as a scientific notation. (The radius of a period on this page is small)
Answer:
its easy solve it with calculator
Step-by-step explanation: