**Answer:**

Domain = {x : x ≠ 4 , -4} or (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)

**Step-by-step explanation:**

<u>**TO FIND :-**</u>

- Domain of

<u>**SOLUTION :-**</u>

Domain of a function is a value for which the function is valid.

The function is valid until the denominator is 0.

So make sure that the denominator must not be 0.

Find the values of x for which the denominator becomes 0. To find it , you'll have to solve the above inequality.

We can say that <u>**4 & -4 can't be domains**</u> because these values will make the function undefined.

Now try putting values of x such that -4 < x < 4. You'll observe that the function will be valid for all those values of x between -4 & 4.

<u>**CONCLUSION :-**</u>

The function will be valid for any value of 'x' except 4 & -4. So in :-

Interval notation , it can be written as → (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)

Set builder notation , it can be written as → {x : x ≠ 4 , -4}

**Answer:**

14.81% probability an individual large-cap domestic stock fund had a three-year return of at least 19%

**Step-by-step explanation:**

**Problems of normally distributed samples are solved using the z-score formula.**

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

**In this problem, we have that:**

**What is the probability an individual large-cap domestic stock fund had a three-year return of at least 19%**

This is 1 subtracted by the pvalue of Z when X = 0.19. So

has a pvalue of 0.8519

1 - 0.8519 = 0.1481

14.81% probability an individual large-cap domestic stock fund had a three-year return of at least 19%

**Answer:**

BC 136m, AB 89m

**Step-by-step explanation:**

Find the diagram attached

**According to sin rule;**

a/sinA = b/sinB = c/sinC

**From the diagram;**

b = 120m

<B = 60degrees

<C = 40degrees

**From the sine formula**

b/sinB = c/sinC

120/sin60 = c/sin40

csin60 = 120sin40

c = 120sin40/sin60

c = 120(0.6428)/0.8660

c = 77.1345/0.8660

c = 89.06

**c = AB = 89m**

Get BC;

According to the sine rule

a/sinA = b/sinB

a/sin(180-100) = 120/sin60

a/sin80 = 120/sin60

asin60 = 120sin80

a = 120sin80/sin60

a = 120(0.9848)/0.8660

a = 118.177/0.8550

a = 136.46

**Hence a = BC = 136m**

Answer: its <

Step-by-step explanation:

**Answer:**

the answer is c) 182.25

**Step-by-step explanation:**

The information provided gives you a scale that will ultimately allow you to determine the height of the larger cylinder.

Since it tells us the two are similar, we can use the scale to solve for the second height.

Set up your math like this:

h represents the height you are trying to find.

using a common multiple, you can solve for h.

16 times 4 is 64. so 729 divided by 4 is 182.25