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Archy [21]
2 years ago
12

Please help!!

Mathematics
1 answer:
crimeas [40]2 years ago
3 0
1)~3x+12=3(x+4)\\\\ 2)~7y-7=7(y-1)\\\\ 3)~5x+30y=5(x+6y)\\\\ 4)~8m+36n=4(2m+9n)\\\\ 5)~6a^2+27=3(2a^2+9)\\\\ 6)~4y^2-24y=4y(y-6)\\\\ 7)~21cd-3d=3d(7d-1)\\\\ 8)~14gh-18h=2h(7g-9)\\\\ 9)~15a^2b-30ab=15ab(a-2)\\\\ 10)~16bc^2+24bc=8bc(2c+3)
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sergejj [24]
Answer is A
Because 43-4=39
39/13=3
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PLS HELP WILL MARK BRAINLIEST<br> Question 13
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Answer:

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A rectangular tank 60 cm long and 50 cm wide is /5 full of water. When 24 liters of water are added, the water level rises to th
bija089 [108]

Answer:

The tank is 10cm high

Step-by-step explanation:

Given

L=60cm -- length

W=60cm -- width

x = \frac{1}{5} --- water lever

Addition = 24L

Required

The height of the tank

Let y represents the remaining fraction before water is added.

So:

y + x = 1

Make y the subject

y = 1 - x

y = 1 - \frac{1}{5}

Solve

y = \frac{5 - 1}{5}

y = \frac{4}{5}

Represent the volume of the tank with v

So:

y * v = 24L

Make v the subject

v = \frac{24L}{y}

Substitute: y = \frac{4}{5}

v = \frac{24L}{4/5}

v = 30L

Represent the height of the tank with h;

So, the volume of the tank is:

v = lwh

Make h the subject

h = \frac{v}{lw}

Substitute values for v, l and w

h = \frac{30L}{60cm * 50cm}

Convert 30L to cm^3

h = \frac{30*1000cm^3}{60cm * 50cm}

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8 0
3 years ago
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frosja888 [35]
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4 0
3 years ago
How would you solve 4n-5&lt;-9n+47 to get the solution?
fredd [130]

Answer:

n<4

Step-by-step explanation:

4n-5<-9n+47

13n<52 |:13

n<4

4 0
3 years ago
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