Help whats 13×2/3?<br>I give brainliest ofc :)

Think about how you can use absolute value notation to express the distance between two points on a coordinate graph. For each p

vagabundo [1.1K]

Answer:

(4, 9) and (-10, -8)

Step-by-step explanation:

8 0

3 years ago

How do you solve X for this

kaheart [24]

So it's part of a diameter with the 40, so you should have taken 180-40=140 then it should have been set equal to 140. So 22x+8=140 then 22x=132 then 132÷22=6 so x=6

8 0

2 years ago

Plz help me well mark brainliest if you are correct!..

egoroff_w [7]

Answer:

your answer should be -4/5

6 0

2 years ago

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If