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const2013 [10]
3 years ago
15

Becky wants to fence in a rectangular play area for her dog. If she wants the length of the play area to be 9 feet longer than h

alf its width, what should the dimensions of the play area be? Write the dimensions algebraically
Mathematics
2 answers:
AysviL [449]3 years ago
8 0

Answer: lenght = 9ft + W/2

widht = W

Step-by-step explanation:

if we define L as the lenght, and W as the width, we have that:

L = 9ft + W/2

Then the dimensions are the lenght and the width, and with only one of these two variables, we have all the dimensions, that are

lenght = 9ft + W/2

widht = W

Firdavs [7]3 years ago
4 0

Answer:

The dimension of the play area written algebraically is y²/2 + 9y

Step-by-step explanation:

Let the be x and the width be y

If the length is to be 9 feet longer than half the width,

hence y/2 + 9 = x

hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y

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Step-by-step explanation:

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Billy will earn $8 per hour and work 12 hours per week how much will he earn in one week​
wolverine [178]

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The answer is simple. If there is $8 an hour and works for 12 hours, just multiply 8 by 12, which is 96. He will earn $96 in a week

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2 years ago
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96 Square inches because if you multiply every side with each length you get 96 in2
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3 years ago
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A patient with end-stage kidney disease has nine family members who are potential kidney donors. How many possible orders are th
eduard

Answer: 504

Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

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