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const2013 [10]
2 years ago
15

Becky wants to fence in a rectangular play area for her dog. If she wants the length of the play area to be 9 feet longer than h

alf its width, what should the dimensions of the play area be? Write the dimensions algebraically
Mathematics
2 answers:
AysviL [449]2 years ago
8 0

Answer: lenght = 9ft + W/2

widht = W

Step-by-step explanation:

if we define L as the lenght, and W as the width, we have that:

L = 9ft + W/2

Then the dimensions are the lenght and the width, and with only one of these two variables, we have all the dimensions, that are

lenght = 9ft + W/2

widht = W

Firdavs [7]2 years ago
4 0

Answer:

The dimension of the play area written algebraically is y²/2 + 9y

Step-by-step explanation:

Let the be x and the width be y

If the length is to be 9 feet longer than half the width,

hence y/2 + 9 = x

hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y

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The side of a square measures (2x − 5) units. Part A: What is the expression that represents the area of the square? Show your w
kolbaska11 [484]

A. The area of a square is given as:

<span>A = s^2 </span>

Where s is a measure of a side of a square. s = (2 x – 5) therefore,

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Expanding,

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<span>B. The degree of a polynomial is the highest exponent of the variable x, in this case 2. Therefore the expression obtained in part A is of 2nd degree.</span>

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2 years ago
Miss Kirkland Works 40 hours on Mondays in 8 hours on Tuesdays in the school library during one week in May she worked 1/4 of he
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Answer:

She worked 12 hours for the week

Step-by-step explanation:

Given that :

Hours worked :

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Tuesdays = 8 hours

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