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nasty-shy [4]
3 years ago
13

(4y-18)+(y+14)+(6x11)=180

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

firstly remove the bracket

4y-18+y+14+6*11=180

collect like terms

4y+y-18+14+66=180

5y +62=180

5y =180-62

5y=118

divide both side by 5

5y/5=118/5

y=23.6

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Step-by-step explanation:

= (x + y)(x + 6y)

= x \times x + x \times 6y + y \times x + y \times 6y

=  {x}^{2}  + 6xy + xy + 6 {y}^{2}

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Given: sin theta=2/3 and is in the second quadrant; evaluate the following expression. sin 2 theta
Dmitry [639]

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Step-by-step explanation:

Process

1.- Find the cos a

  Opposite side = 5

  Hypotenuse = 13

  Adjacent side = ?

  Adjacent side² = 13² - 5²

                          = 169 - 25

                          = 144

 Adjacent side = 12

cos a = 12/13

2.- Find the sin b

sin b = 5/13

3.- Use the formula below to find sin(a + b)

              sin (a + b) = sina cosb  + sin b cos a

- Substitution

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- Simplification

              sin (a + b) = -60/169 + 60/13

- Result

              sin(a + b) = 0                        

Step-by-step explanation:

4 0
3 years ago
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