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romanna [79]
3 years ago
9

I don’t understand number 23

Mathematics
2 answers:
Andrews [41]3 years ago
8 0

Answer: 70 minutes

Step-by-step explanation: simply do 420/6 to find out the number of minutes it will take.

You could also do this as a ratio of minutes to cartons 1:6 and find out how many times you must multiply 6 cartons to get to 420 cartons. That number is 70 so just multiply the 1 for the number of minutes because in ratios you must multiply by the same value for each number in the ratio.

N76 [4]3 years ago
5 0

Answer:

70 minutes

Step-by-step explanation:

420/6=70 mins

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Factorize 8(a+b)^2-6(a+b)-9​
MAVERICK [17]

Answer:

(

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2

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Step-by-step explanation:

5 0
3 years ago
Area and Circumference of Circles
Thepotemich [5.8K]

Pi(\pi) is the ratio of circumference to diameter for any circle.

Perimeter is the distance around a circle.

Circumference of circle C = \pi d.

Perimeter of circle = 2 \pi r

What is circle ?

A circle is a spherical shape without boundaries or edges.

A circle is a closed, curved object with two dimensions in geometry.

Consider two small arcs AB and CD of two circles of radii x and y units, both of which make an angle of measure θ at the centers P and Q respectively.

For smaller values of θ, the arc length AB is almost equal to the length of the line segment \bar{AB}. Similarly, arc CD ≅ \bar{CD}.

Using the SAS rule of triangle similarity, we can say that APB and CQD are similar triangles because their angles are the same and their ratios are AP: PB = CQ: QD = 1: 1. So, it stands to reason that AB: AP = CD: CQ.

Circumference = \pi \times diameter or circumference = 2\pi \times radius if this constant equals some value.

So it was proved.

Learn more about Circle click on this:

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7 0
1 year ago
A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the poli
pishuonlain [190]

Complete question:

A police car is located 50 feet to the side of a straight road. A red car is driving along the road in the direction of the police car and is 130 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road.

Answer:

The red car is traveling along the road at 80.356 ft/s

Step-by-step explanation:

Given

Police car is 50 feet side off the road

Red car is 130 feet up the road

Distance between them is decreasing at the rate of 75 feet per sec

Let x be how far the police is off the road.

Let y be how far the red car is up the road.  

Let h be the distance between the police and the red car.

This forms a right triangle so we can use the Pythagorean theorem, to solve for h

h² = x² + y²

h² = 50² + 130²

h² = 19400

h = √19400

h = 139.284 ft

Again;

Let dx/dt be how fast the police is traveling toward the road.

Let dy/dt  be how fast the red car is traveling along the road.

Let dh/dt be how fast the distance between the police and the car is decreasing.

Recall that, h² = x² + y² (now differentiate with respect to time, t)

2h(dh/dt) = 2x(dx/dt) + 2y(dy/dt)

divide through by 2

h(dh/dt) = x(dx/dt) + y(dy/dt)

since the police car is not, dx/dt = 0

and dy/dt is the how fast is the red car actually traveling along the road

139.284(75) = 50(0) + 130(dy/dt)

10446.3 = 0 + 130(dy/dt)

dy/dt = 10446.3 / 130

dy/dt = 80.356 ft/s

Therefore, the red car is traveling along the road at 80.356 ft/s

6 0
3 years ago
$850 flat fee for 31 to 50 guests
AlladinOne [14]

Answer:

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Step-by-step explanation:

you stupio person you told on me your deab

4 0
3 years ago
In a certain region, the equation  y=19.485x+86.912  models the amount of a homeowner’s water bill, in dollars, where x is the n
DanielleElmas [232]

Answer:

It's choice 2.

Step-by-step explanation:

y=19.485x+86.912

The 19.485 is the slope of the graph of this equation.  This gives the rate of change of the amount of the bill (above $86.912)  for  each added resident (x).

5 0
3 years ago
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