First, you gotta distribute the -4 to x-2,
<span>y+6=-4(X-2)
y+6=-4x+8
Then, subtract both sides by 6,
y+6-6=-4x+8-6
y=-4x+2
Done</span>
25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
$27.99
Step-by-step explanation:
34.99*.20 = 6.998
34.99-6.998 = 27.992
the answer rounded would be $27.99
Hope this helps
It's 14.285714%
So, simplified it would be 14.3% because you round the 2 up since theres an 8 behind it.
