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Vladimir [108]
3 years ago
11

In a race in which twelve automobiles are entered and there are no​ ties, in how many ways can the first three finishers come​ i

n?
Mathematics
2 answers:
Ostrovityanka [42]3 years ago
5 0

Answer:

1320 ways

Step-by-step explanation:

In a race in which twelve automobiles are entered and there are no ties.

We have to find the ways in which first three finishers come in.

In these questions when order is fixed means when first, second and third positions are fixed (First comes, then second and then third) then we use the permutation to find the number of ways.

3 positions out of 12 automobiles = ^{12}P_{3}=\frac{12!}{(12-3)!}

= \frac{12!}{9!}

= \frac{(12)(11)(10)(9!)}{(9!)}

= 12×11×10

= 1320

In 1320 ways first three automobiles may come in.

k0ka [10]3 years ago
3 0
That is 3 slots
12 in 1st slot
11 in 2nd
10 in 3rd

so that is 12*11*10 or 1320 ways
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Here is another easy question to answer: What is the mean of the data sets {41,19,29,12,49,30}, {28,22,10,30,15}, {49,24,18,53,3
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Answer:

Data set A {41,19,29,12,49,30} = 30

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Step-by-step explanation:

Data set A {41,19,29,12,49,30} =

Mean = Sum of terms/ number of terms

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Mean = 41 + 19 + 29 + 12 + 49 + 30/ 6

= 180/6 = 30

Data set B {28,22,10,30,15} =

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Data set C{49,24,18,53,38} =

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= 182/5 = 36.4

7 0
3 years ago
Solve for x. Round your answer to the nearest tenth (0.1)
Marizza181 [45]

Answer:

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Step-by-step explanation:

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Substitute:

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Use a calculator:

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Answer:

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