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solong [7]
2 years ago
13

A man buys eggs at GH 4.50 per crate of 30 eggs. He finds that 20% of the eggs are broken but sells the rest at GH¢ 3.00 a dozen

. Find his percentage profit to the nearest whole number.​
Mathematics
1 answer:
AleksAgata [21]2 years ago
6 0
33.33% so i guess 33%
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85 is what percent of 170?
natta225 [31]
121.4285%
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3 years ago
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Examine the following expression.
svetoff [14.1K]

Answer:

True expressions:

  • The constants, -3 and -8, are like terms.  
  • The terms 3 p and p are like terms.  
  • The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.
  • The expression contains six terms.
  • Like terms have the same variables raised to the same powers.

Step-by-step explanation:

The expression is:

p² - 3 + 3p - 8 + p + p³

False expressions:

  • The terms p squared, 3 p, p, and p cubed have variables, so they are like terms.  (They don't have the same exponents)
  • The terms p squared and p cubed are like terms.    (They don't have the same exponents)
  • The expression contains seven terms. (It contains 6 terms)
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3 years ago
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Alecsey [184]
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3 years ago
The radius of a circle is 18 yards. What is the circle's area?<br> Use 3.14 for ​.
IrinaVladis [17]

Solution:

<u>We know that:</u>

  • Radius: 18 yards
  • πr² = Area of circle
  • π = 3.14

<u>Finding the area of the circle:</u>

  • (π)(r²) = Area of circle
  • => (3.14)(18²) = Area of circle
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3 0
2 years ago
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There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Aca
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Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

P(A) = \frac{9}{92}

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

P(B) = \frac{10}{91}

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

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