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Furkat [3]
3 years ago
12

Is 7.525225222....... rational or irrational ?

Mathematics
1 answer:
ankoles [38]3 years ago
3 0

Answer:

It is irrational

Step-by-step explanation:

7.525225222....... is non terminating non reoccurring

Therefore it is irrational

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1/3 (6x - 9) + 3x - 8
Lena [83]

The answer is 5x-11

You have to distrivute 1/3 into 6x and -9 and after you have your answer for those you can combine like terms.

4 0
2 years ago
CAN SOMEONE HELP MEPLZ
Sholpan [36]

Answer:

Step-by-step explanation:

<h2>A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. </h2><h2>y=-16x^2+129x+119 </h2><h2>y=−16x  </h2><h2>2 </h2>

+129x+119

8 0
2 years ago
4x−5 for x=10<br><br> Please, I really need the answer.
hichkok12 [17]

Answer:

4(10)-5=35

Step-by-step explanation:

4(10)=40-5=35

4(10) is the same as 4x10

So think about it like 4x10-5

I hope this helps ;}

8 0
2 years ago
Determine the value of x.
Artyom0805 [142]

Answer: 1) -5.8

Step-by-step explanation:

in order to solve the problem you have to put it together:

9x-5 = 14x+24

then go from there : subtract 24 on both sides , then subtract 9x on both sides , that’ll leave you with : -29 = 5x

so from there we divide , giving us x= -5.8

7 0
3 years ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
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