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sweet-ann [11.9K]
2 years ago
8

Which solid object has the highest specific heat? -aluminum -silver -wood -ice

Chemistry
2 answers:
Irina-Kira [14]2 years ago
6 0
The aluminum's temperature changed less than the copper's did under the same conditions. Thus, the aluminum must require more energy to change its temperature. Therefore, aluminum has the higher specific heat.
jolli1 [7]2 years ago
5 0

Answer:

Aluminum

Explanation:

Because aluminum temperature changed less than the copper's did under the same condition. This, the aluminum must require more energy to change its temperature

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Name an alkene that would yield the alcohol above on hydration. (Submit a single name even if there is more than one correct ans
insens350 [35]

Answer:

Enzyme ? ...............

8 0
3 years ago
If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?
mamaluj [8]
Balanced equation: Mg+2HCl=MgCl2 + H2
Showing that if Mg is not a limiting factor then 2 moles of HCl on complete reaction liberate 1 mole of Hydrogen
therefore:
1 mole of HCl=35.5g, 40g=x
X= 40/35.5= 1.127mole
2 moles of HCl = 1 moles of Hydrogen
1.127=X
X=1.127/2 = 0.56
the theoretical yield of hydrogen
5 0
3 years ago
Read 2 more answers
The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A
Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

-q_{combust} = q_{water} + q_{calori}

q_{combust} = heat of combustion of benzoic acid

q_{water} = heat energy released to water

q_{calori} = heat energy released to the calorimeter

Therefore,

-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})

1.056*26.42 = [0.987*4.18 + 6.66](T_{f} - 23.32)

27.8995 = [4.12566+6.660](T_{f} - 23.32)

(T_{f} - 23.32) = 27.8995/10.7857 = 2.587

T_{f} = 23.32 + 2.587 = 25.907°C

4 0
3 years ago
Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
3 years ago
A balloon starts out with a volume of 1.3 l at 115.3 kpa. if the temperature is held constant, what would the new volume be if t
Anna35 [415]

The new volume be if the pressure inside the balloon was reduced to 58kpa is 2.58 L.

<h3>What is ideal gas equation?</h3>

Ideal gas equation PV=nRT gives idea about the behavior of gases at different conditions and for this question the equation becomes:

P₁V₁ = P₂V₂, where

P₁ = initial pressure = 115.3 kpa

V₁ = initial volume = 1.3 L

P₂ = final pressure = 58 kpa

V₂ = final volume = ?

On putting all these values in the above equation, we get

V₂ = (115.3)(1.3) / (58) = 2.58 L

Hence resultant volume of gas is 2.58 L.

To know more about ideal gas equation, visit the below link:

brainly.com/question/18909295

#SPJ1

8 0
2 years ago
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