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2 years ago

I AM GIVING AWAY 80 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry

2 answers:

dangina [55]2 years ago

6 0

Answer:

thank you so much!!!!!!!!!!!!

egoroff_w [7]2 years ago

6 0

Answer:

HIII I REALY NEED HELP WITH SOME HISTORY QUESTIONS

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Match the atoms which might substitute for one another. Match the items in the left column to the items in the right column.

valkas [14]

Atoms which might substitute for one another can be found in the same column in the periodic table.
So, since Si and C are found in the same column, they can substitute each other.
1. Si = C
2. K = Na
3. Nb = V
4. Cu = Ag
5. P = As
6. Mg = Ca

8 0

2 years ago

Read 2 more answers

Which of the following phase changes only occurs in solids possessing vapor pressures above atmospheric pressure and at ambient

GuDViN [60]

Answer: The phase change process in which solids gets converted to gases is sublimation.

Explanation:

For the given options:

Option a: Condensation

It is a type of process in which phase change occurs from gaseous state to liquid state at constant temperature.

$Gas\rightleftharpoons Liquid$

Option b: Melting

It is a type of process in which phase change occurs from solid state to liquid state at constant temperature.

$Solid\rightleftharpoons Liquid$

Option c: Sublimation

It is a type of process in which phase change occurs from solid state to gaseous state without passing through the liquid state at constant temperature.

$Solid\rightleftharpoons Gas$

Option d: Deposition

It is a type of process in which phase change occurs from gaseous state to solid state without passing through the liquid state at constant temperature.

$Gas\rightleftharpoons Solid$

Hence, the phase change process in which solids gets converted to gases is sublimation.

4 0

3 years ago

In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant

BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

In another experiment, if 80 $XO_3$ molecules react with 104 $BrZ_3$ molecules. How many $Br_2$ molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of $BrZ_3$ react with 6 molecule of $XO_3$

So, 104 molecules of $BrZ_3$ react with $\frac{104}{8}\times 6=78$ molecule of $XO_3$

From this we conclude that, $XO_3$ is an excess reagent because the given moles are greater than the required moles and $BrZ_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of $Br_2$

From the reaction, we conclude that

As, 8 molecules of $BrZ_3$ react to give 4 molecules of $Br_2$

So, 104 molecules of $BrZ_3$ react to give $\frac{104}{8}\times 4=52$ molecules of $Br_2$

Hence, the number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

4 0

3 years ago

Which of these reactions is an addition reaction?

Akimi4 [234]

Answer:

https://smartlyhelper.com/chemistry/question14062929

I found the answer in this link

6 0

2 years ago

The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2

pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0

3 years ago