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Vesnalui [34]
3 years ago
15

I AM GIVING AWAY 80 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
dangina [55]3 years ago
6 0

Answer:

thank you so much!!!!!!!!!!!!

egoroff_w [7]3 years ago
6 0

Answer:

HIII I REALY NEED HELP WITH SOME HISTORY QUESTIONS

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an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m
bogdanovich [222]

Answer:

P_2=1.1x10^6Pa

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

P_1V_1=P_2V_2

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}

Consider that the given initial pressure is also equal to Pa:

P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa

Which stands for a pressure increase when volume decreases.

Regards.

4 0
3 years ago
SHOW WORK
horsena [70]
10.0gNaCl/2.0Lsolution= 5.0g/L
4 0
3 years ago
Trans-2-butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm−1); however, ir spectroscopy is
Elza [17]
However <em>trans</em>-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.

1)  3010-3100 cm⁻¹:
                               As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.

2)  675-1000 cm⁻¹:
                             Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.
3 0
3 years ago
??????????????? why ????????????????
stealth61 [152]

Answer:

because

Explanation:

4 0
3 years ago
Read 2 more answers
How many grams of a 32.9% potassium sulfate solution would contain 181.6 g potassium
Anna007 [38]

Answer:

grams of solution = 551.98 g

Explanation:

Given data:

Percentage of solution = 32.9

Mass of solute = 181.6 g

Grams of solvent = ?

Solution:

Formula:

%  = [grams of solute / grams of solution] × 100

Now we will put the values in formula.

32.9 = [ 181.6 g / grams of solution] × 100

grams of solution = 181.6 g × 100 / 32.9

grams of solution = 18160 g /32.9

grams of solution = 551.98 g

8 0
3 years ago
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