Answer: 48.6 kJ/mol
Explanation:
The balanced chemical reaction is,

The expression for enthalpy change is,
![\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28reactant%29%5D)
![\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_6H_6}\times \Delta H_{C_6H_6})]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%28n_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_%7BCO_2%7D%29%2B%28n_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_%7BH_2O%7D%29%5D-%5B%28n_%7BO_2%7D%5Ctimes%20%5CDelta%20H_%7BO_2%7D%29%2B%28n_%7BC_6H_6%7D%5Ctimes%20%5CDelta%20H_%7BC_6H_6%7D%29%5D)
where,
n = number of moles
(as heat of formation of substances in their standard state is zero
Now put all the given values in this expression, we get
![-6534.0=[(12\times -393.5)+(6\times -285.8)]-[(15\times 0)+(2\times \Delta H_{C_6H_6})]](https://tex.z-dn.net/?f=-6534.0%3D%5B%2812%5Ctimes%20-393.5%29%2B%286%5Ctimes%20-285.8%29%5D-%5B%2815%5Ctimes%200%29%2B%282%5Ctimes%20%5CDelta%20H_%7BC_6H_6%7D%29%5D)

Therefore, the enthalpy change for benzene is 48.6 kJ/mol
25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)
<h3>Explanation</h3>
The process:
.
How many moles of this process?
Relative atomic mass from a modern periodic table:
- K: 39.098;
- N: 14.007;
- O: 15.999.
Molar mass of
:
.
Number of moles of the process = Number of moles of
dissolved:
.
What's the enthalpy change of this process?
for
. By convention, the enthalpy change
measures the energy change for each mole of a process.
.
The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.
Answer:
Should be A, but also I think there should be an arrow between O2 and 2H2O
Answer:
ptotal=pA+pB+pC
Explanation:
it is defined as the sum le the pressures le each individual gas ^
P2 = 40 atm
Explanation:
Given:
P1 = 2 atm
V1 = 1200 L
V2 = 60 L
P2 = ?
Using Boyle's law and solving for P2,
P1V1 = P2V2
P2 = (V1/V2)P1
= (1200 L/60 L)(2 atm)
= 40 atm