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Setler79 [48]
3 years ago
11

if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution

Chemistry
1 answer:
Liula [17]3 years ago
5 0

Answer:

Solute = 5 mL; solution = 250 mL  

Explanation:

The formula for percent by volume is

\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%

If you have 250 mL of a solution that is 2 % v/v,

\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}

If there is no change of volume on mixing,

Volume of solution = 250 mL

 -Volume of solute = <u>     </u><u>5</u><u>      </u>

 Volume of solvent = 245 mL

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ANSWER: 
</span>\boxed{\frac{3}{4}}
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When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

<h3>What is Limiting reagent ?</h3>

Limiting reagents are the substances that are completely consumed first in a chemical reaction.

Given ;

  • Amopunt of Zn : 1 mole
  • Amount of O₂ : 2 mole

Given equation ;

2Zn + O₂ --> 2ZnO

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