Answer:
9
Step-by-step explanation:
3/4=0.75
1/12=0.0833333333
(3/4)/(1/12)=9
9514 1404 393
Answer:
![\sqrt[3]{2197}, 14\frac{1}{3}, 13\frac{12}{8}, \sqrt{213.16}, 15, 2^4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2197%7D%2C%2014%5Cfrac%7B1%7D%7B3%7D%2C%2013%5Cfrac%7B12%7D%7B8%7D%2C%20%5Csqrt%7B213.16%7D%2C%2015%2C%202%5E4)
Step-by-step explanation:
The values of the given numbers, in order, rounded to 1 decimal place are ...
![\begin{array}{cc}\sqrt{213.16}&14.6\\14\frac{1}{3}&14.3\\15&15.0\\13\frac{12}{8}&14.5\\2^4&16.0\\\sqrt[3]{2197}&13.0\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7D%5Csqrt%7B213.16%7D%2614.6%5C%5C14%5Cfrac%7B1%7D%7B3%7D%2614.3%5C%5C15%2615.0%5C%5C13%5Cfrac%7B12%7D%7B8%7D%2614.5%5C%5C2%5E4%2616.0%5C%5C%5Csqrt%5B3%5D%7B2197%7D%2613.0%5Cend%7Barray%7D)
Their least-to-greatest ordering is shown above.
Below is the solution:
<span>Using 2 equations:
Quantity: c + p = 10 lbs
Value::: 5.6c + 2.3p = 3.29*10 dollars
</span><span>Multiply thru the Quantity Eq. by 560
Multiply thru the Value Eq. by 100
</span><span>560c + 560p = 5600
</span><span>560c + 230p = 3290
</span><span>Subtract and solve for "p":
330p = 2310
p = 7 lbs (amt. of peanuts needed)
</span><span>Solve for "c" using c+p = 10
c + 7 = 10
c = 3 lbs (amt. of cashews needed)</span>
Answer:
J (-6 , -2), J': (-6 , 2), J'': (6 , 2)
Step-by-step explanation:
J (-6 , -2)
J': (-6 , 2)
J'': (6 , 2)
