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3 years ago

Point J is located at (-6, -2) on the coordinate plane. Point J is reflected over the

Mathematics

1 answer:

solong [7]3 years ago

7 0

Answer:

J (-6 , -2), J': (-6 , 2), J'': (6 , 2)

Step-by-step explanation:

J (-6 , -2)

J': (-6 , 2)

J'': (6 , 2)

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Write the following word phase as a mathematical equation. The sum of 7 and twice a number, squared.

agasfer [191]

Answer:

$(7+(2n))^2$

You don't technically need the ( ) around the 2n, but I included them to avoid confusion.

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3 years ago

Leslie has 8 pencils.

Rudiy27

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3 years ago

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Find a rational number halfway in between the two numbers. three sevenths and one tenth

strojnjashka [21]

Answer:
The rational number is : 37/140

Explanation:
The first number given is three sevenths which can be written as 3/7
The second number given is one tenth which can be written as 1/10

Now, we want to get the midpoint between these two numbers. The midpoint can be calculated as follows:
midpoint = (first number + second number) / 2
midpoint = [(3/7) + (1/10)] / 2
midpoint = 37/140

Hope this helps :)

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3 years ago

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If y varies inversely to x and y=9 when x=-6 find x when y=3

Minchanka [31]

Answer: y =21

Step-by-step explanati

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2 years ago

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Pls help me solve this question, also include step by step calculation ya. Thks

sp2606 [1]

$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

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1 year ago