Answer:
Step-by-step explanation:
A1. C = 104°, b = 16, c = 25
Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°
A = 180-C-B = 37.6°
Law of Sines: a = c·sinA/sinC ≅ 15.7
A2. B = 56°, b = 17, c = 14
Law of Sines: C = arcsin[c·sinB/b] ≅43.1°
A = 180-B-C = 80.9°
Law of Sines: a = b·sinA/sinB ≅ 20.2
B1. B = 116°, a = 11, c = 15
Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2
A = arccos{(b²+c²-a²)/(2bc) ≅26.5°
C = 180-A-B = 37.5°
B2. a=18, b=29, c=30
Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°
Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°
C = 180-A-B = 75.3°
Since we know that in π radians there are 180°, thus how many radians in 132°?
Answer:
The answer is C.
Step-by-step explanation:
When you add the same negative and positive number it's 0.
For Example:
-5 + 5= 0
1 hour = $8.00
48 hours = $8 x 48
48 hours = $384
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Answer: $384
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Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was <span><span>\$43.25<span>$43.25</span></span>dollar sign, 43, point, 25</span><span>. He had to pay a </span><span><span>\$7<span>$7</span></span>dollar sign, 7</span><span> entrance fee and </span><span><span>\$1.25<span>$1.25</span></span>dollar sign, 1, point, 25</span>for every minute he was on the trampoline.<span><span>Write an equation to determine the number of minutes </span><span><span>(t)<span>(t)</span></span>left parenthesis, t, right parenthesis</span><span> that Raymond was on the trampoline.</span></span>
