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2 years ago

In quadrilateral ABCD AB||CD and m/_2 =31 what is m/_5

Mathematics

1 answer:

Lady_Fox [76]2 years ago

6 0

Answer:

5 is ALSO 31⁰ BECAUSE THE LINES ARE PARALLEL

GIVE BRAINLIEST PLZ

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X - y = 2 4x – 3y = 11

swat32

Answer:

For x - y = 2

You need to find x or y in one of the equations and then substitute that into the other.

So we have;

x-y=2

4x-3y=11

We will take the first equation and find x;

x-y=2

add y to both sides;

x-y+y=2+y

x=2+y

Now we take that answer and substitute it forx in the other equation;

4(2+y)-3y=11

8+4y-3y=11

8+y=11

y=3

Now we have what y equals, so we use it in the first equation to find x;

x-3=2

x=5

So we have;

x=5; y=3

Hope you understand!

And for 4x – 3y = 11

Multiply the first equation by 2 and the second by 3 so that there are the same number of y's in each:

8x - 6y = 22 ...(3)

30x + 6y = -3 ...(4)

Now add (3) and (4) term by term:

38x + 0 = 19

38x = 19

or x = 1/2

Put this back into equation (1)

4*(1/2) - 3y = 11

2 - 3y = 11

Subtract 2 from both sides:

-3y = 9

Divide both sides by -3

y = -3

6 0

3 years ago

Read 2 more answers

what is -8x-9=-21, can someone work out the problem and show me what they did to get there answer so i can understand it?

SashulF [63]

- 8x - 9 = - 21

Add 9 to both sides:

- 8x = - 12

Divide both sides by - 8:

x = -12/-8

x = -3/-2

x = 3/2 OR 1.5

Hope this answer helps :)

6 0

4 years ago

Read 2 more answers

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$